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Problem #46
Ratsional hisoblash
Hard
20 points
Arifmetik amallar
Eng ratsional usulda hisoblang:
6
,
3
⋅
1
,
7
(
6
,
3
1
,
7
−
1
,
7
6
,
3
)
(
6
,
3
+
1
,
7
)
2
−
4
⋅
6
,
3
⋅
1
,
7
\dfrac{\sqrt{6,3\cdot 1,7}\left(\sqrt{\frac{6,3}{1,7}}-\sqrt{\frac{1,7}{6,3}}\right)}{\sqrt{(6,3+1,7)^{2}-4\cdot 6,3\cdot 1,7}}
(
6
,
3
+
1
,
7
)
2
−
4
⋅
6
,
3
⋅
1
,
7
6
,
3
⋅
1
,
7
(
1
,
7
6
,
3
−
6
,
3
1
,
7
)
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