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Problem #44
Proporsiya
Medium
10 points
Arifmetik amallar
Proporsiyadan
X
X
X
ni toping:
X
10
,
5
⋅
0
,
24
−
15
,
15
:
7
,
5
=
9
(
1
11
20
−
0
,
945
:
0
,
9
)
1
3
40
−
4
3
8
:
7
\dfrac{X}{10,5\cdot 0,24-15,15:7,5}=\dfrac{9\left(1\frac{11}{20}-0,945:0,9\right)}{1\frac{3}{40}-4\frac{3}{8}:7}
10
,
5
⋅
0
,
24
−
15
,
15
:
7
,
5
X
=
1
40
3
−
4
8
3
:
7
9
(
1
20
11
−
0
,
945
:
0
,
9
)
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