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Masala №43

Proporsiya

O'rta10 ballArifmetik amallar
Proporsiyadan XX ni toping:
0,125X(1924−2140)⋅8716=(12863−1721)⋅0,70,675⋅2,4−0,02\dfrac{0,125X}{\left(\frac{19}{24}-\frac{21}{40}\right)\cdot 8\frac{7}{16}}=\dfrac{\left(1\frac{28}{63}-\frac{17}{21}\right)\cdot 0,7}{0,675\cdot 2,4-0,02}

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