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Masala №41

Proporsiya

O'rta10 ballArifmetik amallar
Proporsiyadan XX ni toping:
(4−3,5⋅(217−115)):0,16X=327−314:16412384−404960\dfrac{\left(4-3,5\cdot\left(2\frac{1}{7}-1\frac{1}{5}\right)\right):0,16}{X}=\dfrac{3\frac{2}{7}-\frac{3}{14}:\frac{1}{6}}{41\frac{23}{84}-40\frac{49}{60}}

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